## (Solved) Combustion of .487g of quinine (molar mass= 324g/mol) produces

Combustion of .487g of quinine (molar mass= 324g/mol) produces 1.321g CO2, 0.325g H20, and 0.0421g Nitrogen. Determine the empirical and molecular formulas.

Molar mass of CO2 = 12 + 16 * 2 = 44 g

Molar mass of H2O = 1 * 2 + 16 = 18 g

Molar mass of N2 = 14 * 2 = 28 g

Number of moles of CO2 = 1.321/44 = 0.03 (Approx.)

Number of moles of H2O = 0.325/18 =...

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This question was answered on: Oct 15, 2019

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